From cd65de271462b9cc50a130c708f1d2c0e005e953 Mon Sep 17 00:00:00 2001
From: Atsushi <asakai.amsl+github@gmail.com>
Date: Tue, 21 Jan 2020 10:58:02 +0900
Subject: [PATCH] add math descriptions

---
 .../quintic_polynomials_planner.ipynb         | 119 ++++++++++++++----
 1 file changed, 93 insertions(+), 26 deletions(-)

diff --git a/PathPlanning/QuinticPolynomialsPlanner/quintic_polynomials_planner.ipynb b/PathPlanning/QuinticPolynomialsPlanner/quintic_polynomials_planner.ipynb
index 804b7fba..f094ae2c 100644
--- a/PathPlanning/QuinticPolynomialsPlanner/quintic_polynomials_planner.ipynb
+++ b/PathPlanning/QuinticPolynomialsPlanner/quintic_polynomials_planner.ipynb
@@ -2,45 +2,112 @@
  "cells": [
   {
    "cell_type": "markdown",
+   "metadata": {},
    "source": [
     "# Quintic polynomials planner"
-   ],
-   "metadata": {
-    "collapsed": false
-   }
+   ]
   },
   {
    "cell_type": "markdown",
+   "metadata": {},
    "source": [
     "## Quintic polynomials for one dimensional robot motion\n",
     "\n",
-    "We assume a dimensional robot motion $x(t)$ at time $t$ is formulated as a quintic polynomials based on time as follows:\n",
+    "We assume a one-dimensional robot motion $x(t)$ at time $t$ is formulated as a quintic polynomials based on time as follows:\n",
     "\n",
-    "$x(t) = a_0+a_1t+a_2t^2+a_3t^3+a_4t^4$\n",
+    "$x(t) = a_0+a_1t+a_2t^2+a_3t^3+a_4t^4+a_5t^5$ --(1)\n",
     "\n",
-    "a_0, a_1. a_2, a_3 are parameters of the quintic polynomial.\n",
+    "$a_0, a_1. a_2, a_3, a_4, a_5$ are parameters of the quintic polynomial.\n",
+    "\n",
+    "It is assumed that terminal states (start and end) are known as boundary conditions.\n",
+    "\n",
+    "Start position, velocity, and acceleration are $x_s, v_s, a_s$ respectively.\n",
+    "\n",
+    "End position, velocity, and acceleration are $x_e, v_e, a_e$ respectively.\n",
+    "\n",
+    "So, when time is 0.\n",
+    "\n",
+    "$x(0) = a_0 = x_s$ -- (2)\n",
+    "\n",
+    "Then, differentiating the equation (1) with t, \n",
+    "\n",
+    "$x'(t) = a_1+2a_2t+3a_3t^2+4a_4t^3+5a_5t^4$ -- (3)\n",
     "\n",
     "So, when time is 0,\n",
     "\n",
-    "$x(0) = a_0 = x_s$\n",
+    "$x'(0) = a_1 = v_s$ -- (4)\n",
     "\n",
-    "$x_s$ is a start x position.\n",
+    "Then, differentiating the equation (3) with t again, \n",
     "\n",
-    "Then, differentiating this equation with t, \n",
-    "\n",
-    "$x'(t) = a_1+2a_2t+3a_3t^2+4a_4t^3$\n",
+    "$x''(t) = 2a_2+6a_3t+12a_4t^2$ -- (5)\n",
     "\n",
     "So, when time is 0,\n",
     "\n",
-    "$x'(0) = a_1 = v_s$\n",
+    "$x''(0) = 2a_2 = a_s$ -- (6)\n",
     "\n",
-    "$v_s$ is a initial speed for x axis.\n",
+    "so, we can calculate $a_0$, $a_1$, $a_2$ with eq. (2), (4), (6) and boundary conditions.\n",
     "\n",
-    "=== TBD ==== \n"
-   ],
-   "metadata": {
-    "collapsed": false
-   }
+    "$a_3, a_4, a_5$ are still unknown in eq(1).\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "We assume that the end time for a maneuver is $T$, we can get these equations from eq (1), (3), (5):\n",
+    "\n",
+    "$x(T)=a_0+a_1T+a_2T^2+a_3T^3+a_4T^4+a_5T^5=x_e$ -- (7)\n",
+    "\n",
+    "$x'(T)=a_1+2a_2T+3a_3T^2+4a_4T^3+5a_5T^4=v_e$ -- (8)\n",
+    "\n",
+    "$x''(T)=2a_2+6a_3T+12a_4T^2+20a_5T^3=a_e$ -- (9)\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "From eq (7), (8), (9), we can calculate $a_3, a_4, a_5$ to solve the linear equations.\n",
+    "\n",
+    "$Ax=b$\n",
+    "\n",
+    "$\\begin{bmatrix} T^3 & T^4 & T^5 \\\\ 3T^2 & 4T^3 & 5T^4 \\\\ 6T & 12T^2 & 20T^3 \\end{bmatrix}\n",
+    "\\begin{bmatrix} a_3\\\\ a_4\\\\ a_5\\end{bmatrix}=\\begin{bmatrix} x_e-x_s-v_sT-0.5a_sT^2\\\\ v_e-v_s-a_sT\\\\ a_e-a_s\\end{bmatrix}$\n",
+    "\n",
+    "We can get all unknown parameters now"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Quintic polynomials for two dimensional robot motion (x-y)\n",
+    "\n",
+    "If you use two quintic polynomials along x axis and y axis, you can plan for two dimensional robot motion in x-y plane.\n",
+    "\n",
+    "$x(t) = a_0+a_1t+a_2t^2+a_3t^3+a_4t^4+a_5t^5$ --(10)\n",
+    "\n",
+    "$y(t) = b_0+b_1t+b_2t^2+b_3t^3+b_4t^4+b_5t^5$ --(11)\n",
+    "\n",
+    "It is assumed that terminal states (start and end) are known as boundary conditions.\n",
+    "\n",
+    "Start position, orientation, velocity, and acceleration are $x_s, y_s, \\theta_s, v_s, a_s$ respectively.\n",
+    "\n",
+    "End position, orientation, velocity, and acceleration are $x_e, y_e. \\theta_e, v_e, a_e$ respectively.\n",
+    "\n",
+    "Each velocity and acceleration boundary condition can be calculated with each orientation.\n",
+    "\n",
+    "$v_{xs}=v_scos(\\theta_s), v_{ys}=v_ssin(\\theta_s)$\n",
+    "\n",
+    "$v_{xe}=v_ecos(\\theta_e), v_{ye}=v_esin(\\theta_e)$\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
   }
  ],
  "metadata": {
@@ -52,25 +119,25 @@
   "language_info": {
    "codemirror_mode": {
     "name": "ipython",
-    "version": 2
+    "version": 3
    },
    "file_extension": ".py",
    "mimetype": "text/x-python",
    "name": "python",
    "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython2",
-   "version": "2.7.6"
+   "pygments_lexer": "ipython3",
+   "version": "3.7.5"
   },
   "pycharm": {
    "stem_cell": {
     "cell_type": "raw",
-    "source": [],
     "metadata": {
      "collapsed": false
-    }
+    },
+    "source": []
    }
   }
  },
  "nbformat": 4,
- "nbformat_minor": 0
-}
\ No newline at end of file
+ "nbformat_minor": 1
+}