Files
coffeescript/test/test_operations.coffee
2010-12-03 13:01:13 -05:00

263 lines
4.6 KiB
CoffeeScript

# binary (2-ary) math operators do not require spaces
(->
a = 1
b = -1
ok a*-b is 1
ok a*+b is -1
ok a/-b is 1
ok a/+b is -1
)()
# operators should respect new lines as spaced
(->
a = 123 +
456
ok a is 579
b = "1#{2}3" +
"456"
ok b is '123456'
)()
# multiple operators should space themselves
ok + +1 is - -1
# bitwise operators
(->
ok (10 & 3) is 2
ok (10 | 3) is 11
ok (10 ^ 3) is 9
ok (10 << 3) is 80
ok (10 >> 3) is 1
ok (10 >>> 3) is 1
num = 10; ok (num <<= 3) is 80
num = 10; ok (num >>= 3) is 1
num = 10; ok (num >>>= 3) is 1
num = 10; ok (num &= 3) is 2
num = 10; ok (num ^= 3) is 9
num = 10; ok (num |= 3) is 11
)()
# `instanceof`
(->
ok new String instanceof String
ok new Boolean instanceof Boolean
# `instanceof` supports negation by prefixing the operator with `not`
ok new Number not instanceof String
ok new Array not instanceof Boolean
)()
## compound assignment operators
(->
# boolean operators
(->
a = 0
a or= 2
eq a, 2
b = 1
b or= 2
eq b, 1
c = 0
c and= 2
eq c, 0
d = 1
d and= 2
eq d, 2
# ensure that RHS is treated as a group
e = f = false
e and= f or true
ok e is false
)()
# compound assignment as a sub expression
(->
[a, b, c] = [1, 2, 3]
ok (a + b += c) is 6
ok a is 1
ok b is 5
ok c is 3
)()
# compound assignment should be careful about caching variables
(->
count = 0
list = []
list[++count] or= 1
eq list[1], 1
eq count, 1
list[++count] ?= 2
eq list[2], 2
eq count, 2
list[count++] and= 'two'
eq list[2], 'two'
eq count, 3
base = ->
++count
base
base().four or= 4
eq base.four, 4
eq count, 4
base().five ?= 5
eq base.five, 5
eq count, 5
)()
# compound assignment with implicit objects
(->
obj = undefined
obj ?=
one: 1
ok obj.one is 1
obj and=
two: 2
ok not obj.one
ok obj.two is 2
)()
)()
## `is`,`isnt`,`==`,`!=`
(->
# `==` and `is` should be interchangeable.
(->
a = b = 1
ok a is 1 and b == 1
ok a == b
ok a is b
)()
# `!=` and `isnt` should be interchangeable.
(->
a = 0
b = 1
ok a isnt 1 and b != 0
ok a != b
ok a isnt b
)()
)()
## `in`, `of`
(->
# `in` should check if an array contains a value using `indexOf`
# `of` should check if a property is defined on an object using `in`
(->
arr = [1]
ok 0 of arr
ok 1 in arr
# prefixing `not` to `in and `of` should negate them
ok 1 not of arr
ok 0 not in arr
)()
# `in` should be able to operate on an array literal
(->
ok 2 in [0, 1, 2, 3]
ok 4 not in [0, 1, 2, 3]
arr = [0, 1, 2, 3]
ok 2 in arr
ok 4 not in arr
# should cache the value used to test the array
arr = [0]
val = 0
ok val++ in arr
ok val++ not in arr
val = 0
ok val++ of arr
ok val++ not of arr
)()
# `of` and `in` should be able to operate on instance variables
(->
obj = {
list: [2,3]
in_list: (value) -> value in @list
not_in_list: (value) -> value not in @list
of_list: (value) -> value of @list
not_of_list: (value) -> value not of @list
}
ok obj.in_list 3
ok obj.not_in_list 1
ok obj.of_list 0
ok obj.not_of_list 2
)()
#???: `in` with cache and `__indexOf` should work in argument lists
eq [Object() in Array()].length, 1
#737: `in` should have higher precedence than logical operators.
eq 1, 1 in [1] and 1
#768: `in` should preserve evaluation order.
(->
share = 0
a = -> share++ if share is 0
b = -> share++ if share is 1
c = -> share++ if share is 2
ok a() not in [b(),c()] and share is 3
)()
)()
## CoffeeScript supports chainable operators like Python
(->
ok 100 > 10 > 1 > 0 > -1
ok -1 < 0 < 1 < 10 < 100
# `is` and `isnt` may be chained
ok true is not false is true is not false
ok 0 is 0 isnt 1 is 1
# different comparison operators (`>`,`<`,`is`,etc.) may be combined
ok 1 < 2 > 1
ok 10 < 20 > 2+3 is 5
# some chainable operators can be negated by `unless`
ok (true unless 0==10!=100)
# operator precedence: `|` lower than `<`
eq 1, 1 | 2 < 3 < 4
# preserve references
(->
a = b = c = 1
# `a == b <= c` should become `a === b && b <= c`
ok a == b <= c
)()
# chained operations should evaluate each value only once
(->
a = 0
ok 1 > a++ < 1
)()
#891: incorrect inversion of chained comparisons
(->
ok (true unless 0 > 1 > 2)
ok (true unless (NaN = 0/0) < 0/0 < NaN)
)()
)()