divisors: add note how to use code for reducing [P] - [Q]

This commit is contained in:
narodnik
2022-07-20 12:49:29 +02:00
parent cd030a3c69
commit 6b2cb4380b

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@@ -27,3 +27,8 @@ for i in range(100):
assert V[0][x] == Px
assert V[0][y] == Py
# Note: to reduce D = [P] - [Q], just note that
# D = [P] - [Q]
# = ([P] - [∞]) - ([Q] - [∞])
# = div(f) - div(g) = div(f/g)